Consider the following declarations.
char name[25]; char street[25]; char city[15]; char state[?]; char fullname[?]; char address[?];
What size does the array, state[], need to be in ordered to hold the standard 2 letter abbreviation? 3, 2 letters and the null character
What size does the array, address[], need to be in order to hold the data from city[] and state[] with a comma and one space in between? 19, 14 letters + comma + space + 2 letters + null character
Assume the name[] array is formatted as, lastname, comma, space, firstname. (like Ross, Betsy) What size does fullname[] need to be in order to fit the data from name[], reformatted as first name, space, last name? 24
Write code to rearrange the data from name[] into fullname[] so that it reads first name, space, last name. see below
Write code to find the size of the string in city[]. size = strlen(city);
Move data from city[] and state[] to address[] so there is a comma and one space in between. see below
Assume the street[] array has an address like 1175 N. Main Street. Move the numeric part of the address (1175) to a char array variable called streetnum. Assume there will be a maximum of 5 digits. Declare the variable. see below
4) char *commaptr;
commaptr = strchr(name, ','); find the comma
*commaptr = '\0'; Change comma to null character
so last name portion is now a string.
strcpy(fullname, commaptr+2); First name starts 2 past comma.
strcat(fullname," "); For strcat to work, the space must be
a string, not a character.
strcat(fullname, name)
6) strcpy(address, city); strcat(address, " "); second string has one space strcat(address, state);
7) char streetnum[6];
strncpy(streetnum, street, 5) if you know there are 5 digits OR ptr = strchr(street, ' '); second argument is a character *ptr = '\0'; strcpy(streetnum,street);